Lesson 159
van Emde Boas Trees
Recursive √u split → O(log log u)
1:00How a recursive square-root split of the integer universe gives O(log log u) time for all dictionary operations including successor and predecessor.
By the end, you can
- Compute high(x), low(x), and index(i, j) for any key in a given universe size.
- Describe the recursive structure: √u clusters plus a summary, each a smaller vEB tree.
- Explain the lazy-min trick and why it is the reason inserts into empty subtrees are O(1).
- Trace the successor algorithm on a small example, identifying which branch fires and why.
- Derive that T(u) = T(√u) + O(1) solves to O(log log u) by counting squarerooting steps.
- State the Theta(u) space drawback and name the two standard fixes.
- Identify when vEB beats a balanced BST and why it cannot store arbitrary comparison keys.
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